Solve {l}{12+(-20)-(-11)-1}{35/12-(-11/3)+(-43/8)}

$$\left. \begin{array} { l } { 12 + ( - 20 ) - ( - 11 ) - 1 } \\ { 3 \frac { 5 } { 12 } - ( - 1 \frac { 1 } { 3 } ) + ( - 4 \frac { 3 } { 8 } ) } \end{array} \right.$$

Sort

$$\frac{3}{8},2$$

Solution Steps

Subtract 20 from 12 to get -8.

$$sort(-8-\left(-11\right)-1,\frac{3\times 12+5}{12}-\left(-\frac{1\times 3+1}{3}\right)-\frac{4\times 8+3}{8})$$

The opposite of -11 is 11.

$$sort(-8+11-1,\frac{3\times 12+5}{12}-\left(-\frac{1\times 3+1}{3}\right)-\frac{4\times 8+3}{8})$$

Add -8 and 11 to get 3.

$$sort(3-1,\frac{3\times 12+5}{12}-\left(-\frac{1\times 3+1}{3}\right)-\frac{4\times 8+3}{8})$$

Subtract 1 from 3 to get 2.

$$sort(2,\frac{3\times 12+5}{12}-\left(-\frac{1\times 3+1}{3}\right)-\frac{4\times 8+3}{8})$$

Multiply 3 and 12 to get 36.

$$sort(2,\frac{36+5}{12}-\left(-\frac{1\times 3+1}{3}\right)-\frac{4\times 8+3}{8})$$

Add 36 and 5 to get 41.

$$sort(2,\frac{41}{12}-\left(-\frac{1\times 3+1}{3}\right)-\frac{4\times 8+3}{8})$$

Multiply 1 and 3 to get 3.

$$sort(2,\frac{41}{12}-\left(-\frac{3+1}{3}\right)-\frac{4\times 8+3}{8})$$

Add 3 and 1 to get 4.

$$sort(2,\frac{41}{12}-\left(-\frac{4}{3}\right)-\frac{4\times 8+3}{8})$$

The opposite of -\frac{4}{3} is \frac{4}{3}.

$$sort(2,\frac{41}{12}+\frac{4}{3}-\frac{4\times 8+3}{8})$$

Least common multiple of 12 and 3 is 12. Convert \frac{41}{12} and \frac{4}{3} to fractions with denominator 12.

$$sort(2,\frac{41}{12}+\frac{16}{12}-\frac{4\times 8+3}{8})$$

Since \frac{41}{12} and \frac{16}{12} have the same denominator, add them by adding their numerators.

$$sort(2,\frac{41+16}{12}-\frac{4\times 8+3}{8})$$

Add 41 and 16 to get 57.

$$sort(2,\frac{57}{12}-\frac{4\times 8+3}{8})$$

Reduce the fraction \frac{57}{12} to lowest terms by extracting and canceling out 3.

$$sort(2,\frac{19}{4}-\frac{4\times 8+3}{8})$$

Multiply 4 and 8 to get 32.

$$sort(2,\frac{19}{4}-\frac{32+3}{8})$$

Add 32 and 3 to get 35.

$$sort(2,\frac{19}{4}-\frac{35}{8})$$

Least common multiple of 4 and 8 is 8. Convert \frac{19}{4} and \frac{35}{8} to fractions with denominator 8.

$$sort(2,\frac{38}{8}-\frac{35}{8})$$

Since \frac{38}{8} and \frac{35}{8} have the same denominator, subtract them by subtracting their numerators.

$$sort(2,\frac{38-35}{8})$$

Subtract 35 from 38 to get 3.

$$sort(2,\frac{3}{8})$$

Convert decimal numbers in the list 2,\frac{3}{8} to fractions.

$$2,\frac{3}{8}$$

To sort the list, start from a single element 2.

$$2$$

Insert \frac{3}{8} to the appropriate location in the new list.

$$\frac{3}{8},2$$

Evaluate

$$2,\ \frac{3}{8}$$