Solve {l}{1^{circ}0.8^{2}-0.7^{2}+0.2^3*10}{2^circ8*(7-5)^2+3^2}

$$\left. \begin{array} { l } { 1 ^ { \circ } 0.8 ^ { 2 } - 0.7 ^ { 2 } + 0.2 ^ { 3 } \times 10 } \\ { 2 ^ { \circ } 8 \times ( 7 - 5 ) ^ { 2 } + 3 ^ { 2 } } \end{array} \right.$$

Sort

$$0.23,\ 121$$

Solution Steps

Calculate 0.8 to the power of 2 and get 0.64.

$$sort(1\times 0.64-0.7^{2}+0.2^{3}\times 10,28\left(7-5\right)^{2}+3^{2})$$

Multiply 1 and 0.64 to get 0.64.

$$sort(0.64-0.7^{2}+0.2^{3}\times 10,28\left(7-5\right)^{2}+3^{2})$$

Calculate 0.7 to the power of 2 and get 0.49.

$$sort(0.64-0.49+0.2^{3}\times 10,28\left(7-5\right)^{2}+3^{2})$$

Subtract 0.49 from 0.64 to get 0.15.

$$sort(0.15+0.2^{3}\times 10,28\left(7-5\right)^{2}+3^{2})$$

Calculate 0.2 to the power of 3 and get 0.008.

$$sort(0.15+0.008\times 10,28\left(7-5\right)^{2}+3^{2})$$

Multiply 0.008 and 10 to get 0.08.

$$sort(0.15+0.08,28\left(7-5\right)^{2}+3^{2})$$

Add 0.15 and 0.08 to get 0.23.

$$sort(0.23,28\left(7-5\right)^{2}+3^{2})$$

Subtract 5 from 7 to get 2.

$$sort(0.23,28\times 2^{2}+3^{2})$$

Calculate 2 to the power of 2 and get 4.

$$sort(0.23,28\times 4+3^{2})$$

Multiply 28 and 4 to get 112.

$$sort(0.23,112+3^{2})$$

Calculate 3 to the power of 2 and get 9.

$$sort(0.23,112+9)$$

Add 112 and 9 to get 121.

$$sort(0.23,121)$$

The list values are already in order.

$$0.23,121$$

Evaluate

$$0.23,\ 121$$