Evaluate
396\left(a+b\right)^{2}+101
Expand
396a^{2}+792ab+396b^{2}+101
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2+3-3+99+396\left(a+b\right)^{2}
Add 1 and 1 to get 2.
5-3+99+396\left(a+b\right)^{2}
Add 2 and 3 to get 5.
2+99+396\left(a+b\right)^{2}
Subtract 3 from 5 to get 2.
101+396\left(a+b\right)^{2}
Add 2 and 99 to get 101.
101+396\left(a^{2}+2ab+b^{2}\right)
Use binomial theorem \left(p+q\right)^{2}=p^{2}+2pq+q^{2} to expand \left(a+b\right)^{2}.
101+396a^{2}+792ab+396b^{2}
Use the distributive property to multiply 396 by a^{2}+2ab+b^{2}.
2+3-3+99+396\left(a+b\right)^{2}
Add 1 and 1 to get 2.
5-3+99+396\left(a+b\right)^{2}
Add 2 and 3 to get 5.
2+99+396\left(a+b\right)^{2}
Subtract 3 from 5 to get 2.
101+396\left(a+b\right)^{2}
Add 2 and 99 to get 101.
101+396\left(a^{2}+2ab+b^{2}\right)
Use binomial theorem \left(p+q\right)^{2}=p^{2}+2pq+q^{2} to expand \left(a+b\right)^{2}.
101+396a^{2}+792ab+396b^{2}
Use the distributive property to multiply 396 by a^{2}+2ab+b^{2}.
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