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0-3y=-5
Consider the first equation. Anything times zero gives zero.
-3y=-5
Anything plus zero gives itself.
y=\frac{-5}{-3}
Divide both sides by -3.
y=\frac{5}{3}
Fraction \frac{-5}{-3} can be simplified to \frac{5}{3} by removing the negative sign from both the numerator and the denominator.
4x-\frac{5}{3}=1
Consider the second equation. Insert the known values of variables into the equation.
4x=1+\frac{5}{3}
Add \frac{5}{3} to both sides.
4x=\frac{8}{3}
Add 1 and \frac{5}{3} to get \frac{8}{3}.
x=\frac{\frac{8}{3}}{4}
Divide both sides by 4.
x=\frac{8}{3\times 4}
Express \frac{\frac{8}{3}}{4} as a single fraction.
x=\frac{8}{12}
Multiply 3 and 4 to get 12.
x=\frac{2}{3}
Reduce the fraction \frac{8}{12} to lowest terms by extracting and canceling out 4.
x=\frac{2}{3} y=\frac{5}{3}
The system is now solved.