Solve {l}{0x+14y=460}{x+y=40}

$$\left. \begin{array} { l } { 0 x + 14 y = 460 } \\ { x + y = 40 } \end{array} \right.$$

Solve for x, y

$$x = \frac{50}{7} = 7\frac{1}{7} \approx 7.142857143$$

$$y = \frac{230}{7} = 32\frac{6}{7} \approx 32.857142857$$

Solution Steps

Consider the first equation. Anything times zero gives zero.

$$0+14y=460$$

Anything plus zero gives itself.

$$14y=460$$

Divide both sides by 14.

$$y=\frac{460}{14}$$

Reduce the fraction \frac{460}{14} to lowest terms by extracting and canceling out 2.

$$y=\frac{230}{7}$$

Consider the second equation. Insert the known values of variables into the equation.

$$x+\frac{230}{7}=40$$

Subtract \frac{230}{7} from both sides.

$$x=40-\frac{230}{7}$$

Subtract \frac{230}{7} from 40 to get \frac{50}{7}.

$$x=\frac{50}{7}$$

The system is now solved.

$$x=\frac{50}{7} y=\frac{230}{7}$$