Solve {l}{-8(1-3x)-4x(x+5)}{40x^2-18x}

$$\left. \begin{array} { l } { - 8 ( 1 - 3 x ) - 4 x ( x + 5 ) } \\ { 40 x ^ { 2 } - 18 x } \end{array} \right.$$

Least Common Multiple

$$4x\left(20x-9\right)\left(x^{2}-x+2\right)$$

Solution Steps

Factor the expressions that are not already factored.

$$-4x^{2}+4x-8=4\left(-x^{2}+x-2\right)$$

Identify all the factors and their highest power in all expressions. Multiply the highest powers of these factors to get the least common multiple.

$$4x\left(20x-9\right)\left(x^{2}-x+2\right)$$

Expand the expression.

$$80x^{4}-116x^{3}+196x^{2}-72x$$

Evaluate

$$4\left(-x^{2}+x-2\right),\ 2x\left(20x-9\right)$$