Solve {l}{-3-10:(-2)+3*(-1)-2}{-72:(-9)*4}

$$\left. \begin{array} { l } { - 3 - 10 : ( - 2 ) + 3 \cdot ( - 1 ) - 2 } \\ { - 72 : ( - 9 ) \cdot 4 } \end{array} \right.$$

Evaluate

$$29$$

Solution Steps

Divide 10 by -2 to get -5.

$$-3-\left(-5\right)+3\left(-1\right)-2-\frac{72}{-9}\times 4$$

The opposite of -5 is 5.

$$-3+5+3\left(-1\right)-2-\frac{72}{-9}\times 4$$

Add -3 and 5 to get 2.

$$2+3\left(-1\right)-2-\frac{72}{-9}\times 4$$

Multiply 3 and -1 to get -3.

$$2-3-2-\frac{72}{-9}\times 4$$

Subtract 3 from 2 to get -1.

$$-1-2-\frac{72}{-9}\times 4$$

Subtract 2 from -1 to get -3.

$$-3-\frac{72}{-9}\times 4$$

Divide 72 by -9 to get -8.

$$-3-\left(-8\times 4\right)$$

Multiply -8 and 4 to get -32.

$$-3-\left(-32\right)$$

The opposite of -32 is 32.

$$-3+32$$

Add -3 and 32 to get 29.

$$29$$

Factor

$$29$$