Solve {l}{-31/6-172/3}{1quad2^2}

$$\left. \begin{array} { l } { - 3 \frac { 1 } { 6 } - 17 \frac { 2 } { 3 } } \\ { 1 \quad 2 ^ { 2 } } \end{array} \right.$$

Sort

$$-\frac{125}{6},\ 4$$

Solution Steps

Multiply 3 and 6 to get 18.

$$sort(-\frac{18+1}{6}-\frac{17\times 3+2}{3},1\times 2^{2})$$

Add 18 and 1 to get 19.

$$sort(-\frac{19}{6}-\frac{17\times 3+2}{3},1\times 2^{2})$$

Multiply 17 and 3 to get 51.

$$sort(-\frac{19}{6}-\frac{51+2}{3},1\times 2^{2})$$

Add 51 and 2 to get 53.

$$sort(-\frac{19}{6}-\frac{53}{3},1\times 2^{2})$$

Least common multiple of 6 and 3 is 6. Convert -\frac{19}{6} and \frac{53}{3} to fractions with denominator 6.

$$sort(-\frac{19}{6}-\frac{106}{6},1\times 2^{2})$$

Since -\frac{19}{6} and \frac{106}{6} have the same denominator, subtract them by subtracting their numerators.

$$sort(\frac{-19-106}{6},1\times 2^{2})$$

Subtract 106 from -19 to get -125.

$$sort(-\frac{125}{6},1\times 2^{2})$$

Calculate 2 to the power of 2 and get 4.

$$sort(-\frac{125}{6},1\times 4)$$

Multiply 1 and 4 to get 4.

$$sort(-\frac{125}{6},4)$$

Convert decimal numbers in the list -\frac{125}{6},4 to fractions.

$$-\frac{125}{6},4$$

Evaluate

$$-\frac{125}{6},\ 4$$