Solve {l}{-72/m+144/m=2(f/m+10)*3}{96/m-frac{48}{m}=2(10-frac{f}{m})*3}

$$\left. \begin{array} { l } { - \frac { 72 } { m } + \frac { 144 } { m } = 2 ( \frac { f } { m } + 10 ) \cdot 3 } \\ { \frac { 96 } { m } - \frac { 48 } { m } = 2 ( 10 - \frac { f } { m } ) \cdot 3 } \end{array} \right.$$

Solve for m, f

$$m=1$$

$$f=\frac{2}{t_{1744830465}}$$

$$t_{1744830465}\neq 0$$