Solve {l}{-[-(-[-(2-10)+1]+(-6)(-2+1))-8]-1}{-(2-3)+4+(-5-2+1)-(7-3)-9+20}

$$\left. \begin{array} { l } { - [ - ( - [ - ( 2 - 10 ) + 1 ] + ( - 6 ) ( - 2 + 1 ) ) - 8 ] - 1 } \\ { - ( 2 - 3 ) + 4 + ( - 5 - 2 + 1 ) - ( 7 - 3 ) - 9 + 20 } \end{array} \right.$$

Evaluate

$$10$$

Solution Steps

Subtract 10 from 2 to get -8.

$$-\left(-\left(-\left(-\left(-8\right)+1\right)-6\left(-2+1\right)\right)-8\right)-1-\left(2-3\right)+4-5-2+1-\left(7-3\right)-9+20$$

The opposite of -8 is 8.

$$-\left(-\left(-\left(8+1\right)-6\left(-2+1\right)\right)-8\right)-1-\left(2-3\right)+4-5-2+1-\left(7-3\right)-9+20$$

Add 8 and 1 to get 9.

$$-\left(-\left(-9-6\left(-2+1\right)\right)-8\right)-1-\left(2-3\right)+4-5-2+1-\left(7-3\right)-9+20$$

Add -2 and 1 to get -1.

$$-\left(-\left(-9-6\left(-1\right)\right)-8\right)-1-\left(2-3\right)+4-5-2+1-\left(7-3\right)-9+20$$

Multiply -6 and -1 to get 6.

$$-\left(-\left(-9+6\right)-8\right)-1-\left(2-3\right)+4-5-2+1-\left(7-3\right)-9+20$$

Add -9 and 6 to get -3.

$$-\left(-\left(-3\right)-8\right)-1-\left(2-3\right)+4-5-2+1-\left(7-3\right)-9+20$$

The opposite of -3 is 3.

$$-\left(3-8\right)-1-\left(2-3\right)+4-5-2+1-\left(7-3\right)-9+20$$

Subtract 8 from 3 to get -5.

$$-\left(-5\right)-1-\left(2-3\right)+4-5-2+1-\left(7-3\right)-9+20$$

The opposite of -5 is 5.

$$5-1-\left(2-3\right)+4-5-2+1-\left(7-3\right)-9+20$$

Subtract 1 from 5 to get 4.

$$4-\left(2-3\right)+4-5-2+1-\left(7-3\right)-9+20$$

Subtract 3 from 2 to get -1.

$$4-\left(-1\right)+4-5-2+1-\left(7-3\right)-9+20$$

The opposite of -1 is 1.

$$4+1+4-5-2+1-\left(7-3\right)-9+20$$

Add 4 and 1 to get 5.

$$5+4-5-2+1-\left(7-3\right)-9+20$$

Add 5 and 4 to get 9.

$$9-5-2+1-\left(7-3\right)-9+20$$

Subtract 5 from 9 to get 4.

$$4-2+1-\left(7-3\right)-9+20$$

Subtract 2 from 4 to get 2.

$$2+1-\left(7-3\right)-9+20$$

Add 2 and 1 to get 3.

$$3-\left(7-3\right)-9+20$$

Subtract 3 from 7 to get 4.

$$3-4-9+20$$

Subtract 4 from 3 to get -1.

$$-1-9+20$$

Subtract 9 from -1 to get -10.

$$-10+20$$

Add -10 and 20 to get 10.

$$10$$

Factor

$$2\times 5$$