Solve {l}{(7,2*10^-9)}{(1800*10^-17)}

$$\left. \begin{array} { l } { ( 7,2 \cdot 10 ^ { - 9 } ) } \\ { ( 1800 \cdot 10 ^ { - 17 } ) } \end{array} \right.$$

Sort

$$0,000000000000018;0,0000000072$$

Solution Steps

Calculate 10 to the power of -9 and get \frac{1}{1000000000}.

$$sort(7,2\times \frac{1}{1000000000};1800\times 10^{-17})$$

Multiply 7,2 and \frac{1}{1000000000} to get \frac{9}{1250000000}.

$$sort(\frac{9}{1250000000};1800\times 10^{-17})$$

Calculate 10 to the power of -17 and get \frac{1}{100000000000000000}.

$$sort(\frac{9}{1250000000};1800\times \frac{1}{100000000000000000})$$

Multiply 1800 and \frac{1}{100000000000000000} to get \frac{9}{500000000000000}.

$$sort(\frac{9}{1250000000};\frac{9}{500000000000000})$$

Least common denominator of the numbers in the list \frac{9}{1250000000};\frac{9}{500000000000000} is 500000000000000. Convert numbers in the list to fractions with denominator 500000000000000.

$$\frac{3600000}{500000000000000};\frac{9}{500000000000000}$$

To sort the list, start from a single element \frac{3600000}{500000000000000}.

$$\frac{3600000}{500000000000000}$$

Insert \frac{9}{500000000000000} to the appropriate location in the new list.

$$\frac{9}{500000000000000};\frac{3600000}{500000000000000}$$

Replace the obtained fractions with the initial values.

$$\frac{9}{500000000000000};\frac{9}{1250000000}$$

Evaluate

$$0,0000000072,\ 0,000000000000018$$