Solve {l}{(7x+11)^{2}=49x^{2}}{(m+3)^3=m^3}{(1-3y)^3=1^3}

$$\left. \begin{array} { l } { ( 7 x + 11 ) ^ { 2 } = 49 x ^ { 2 } } \\ { ( m + 3 ) ^ { 3 } = m ^ { 3 } } \\ { ( 1 - 3 y ) ^ { 3 } = 1 ^ { 3 } } \end{array} \right.$$

Solve for x, m, y

$$x=-\frac{11}{14}\approx -0.785714286\text{, }y=0\text{, }m=\frac{-\sqrt{3}i-3}{2}\approx -1.5-0.866025404i$$

$$x=-\frac{11}{14}\approx -0.785714286\text{, }y=\frac{\sqrt{3}i}{6}+\frac{1}{2}\approx 0.5+0.288675135i\text{, }m=\frac{-\sqrt{3}i-3}{2}\approx -1.5-0.866025404i$$

$$x=-\frac{11}{14}\approx -0.785714286\text{, }y=-\frac{\sqrt{3}i}{6}+\frac{1}{2}\approx 0.5-0.288675135i\text{, }m=\frac{-\sqrt{3}i-3}{2}\approx -1.5-0.866025404i$$

$$x=-\frac{11}{14}\approx -0.785714286\text{, }y=0\text{, }m=\frac{-3+\sqrt{3}i}{2}\approx -1.5+0.866025404i$$

$$x=-\frac{11}{14}\approx -0.785714286\text{, }y=\frac{\sqrt{3}i}{6}+\frac{1}{2}\approx 0.5+0.288675135i\text{, }m=\frac{-3+\sqrt{3}i}{2}\approx -1.5+0.866025404i$$

$$x=-\frac{11}{14}\approx -0.785714286\text{, }y=-\frac{\sqrt{3}i}{6}+\frac{1}{2}\approx 0.5-0.288675135i\text{, }m=\frac{-3+\sqrt{3}i}{2}\approx -1.5+0.866025404i$$