Solve {l}{(4+2)}{12+4^4}{2(4+2)}{(4+2)}{4+64+12}

$$\left. \begin{array} { l } { ( 4 + 2 ) } \\ { 12 + 4 ^ { 4 } } \\ { 2 ( 4 + 2 ) } \\ { ( 4 + 2 ) } \\ { 4 + 64 + 12 } \end{array} \right.$$

Sort

$$6,6,12,80,268$$

Solution Steps

Add 4 and 2 to get 6.

$$sort(6,12+4^{4},2\left(4+2\right),4+2,4+64+12)$$

Calculate 4 to the power of 4 and get 256.

$$sort(6,12+256,2\left(4+2\right),4+2,4+64+12)$$

Add 12 and 256 to get 268.

$$sort(6,268,2\left(4+2\right),4+2,4+64+12)$$

Add 4 and 2 to get 6.

$$sort(6,268,2\times 6,4+2,4+64+12)$$

Multiply 2 and 6 to get 12.

$$sort(6,268,12,4+2,4+64+12)$$

Add 4 and 2 to get 6.

$$sort(6,268,12,6,4+64+12)$$

Add 4 and 64 to get 68.

$$sort(6,268,12,6,68+12)$$

Add 68 and 12 to get 80.

$$sort(6,268,12,6,80)$$

To sort the list, start from a single element 6.

$$6$$

Insert 268 to the appropriate location in the new list.

$$6,268$$

Insert 12 to the appropriate location in the new list.

$$6,12,268$$

Insert 6 to the appropriate location in the new list.

$$6,6,12,268$$

Insert 80 to the appropriate location in the new list.

$$6,6,12,80,268$$

Evaluate

$$6,\ 268,\ 12,\ 6,\ 80$$