Solve {l}{(2^{3}+2^3)}{*(3^2+3^2}{+3^2)}

$$\left. \begin{array} { l } { ( 2 ^ { 3 } + 2 ^ { 3 } ) } \\ { \times ( 3 ^ { 2 } + 3 ^ { 2 } } \\ { + 3 ^ { 2 } ) } \end{array} \right.$$

Evaluate

$$432$$

Solution Steps

Calculate 2 to the power of 3 and get 8.

$$\left(8+2^{3}\right)\left(3^{2}+3^{2}+3^{2}\right)$$

Calculate 2 to the power of 3 and get 8.

$$\left(8+8\right)\left(3^{2}+3^{2}+3^{2}\right)$$

Add 8 and 8 to get 16.

$$16\left(3^{2}+3^{2}+3^{2}\right)$$

Calculate 3 to the power of 2 and get 9.

$$16\left(9+3^{2}+3^{2}\right)$$

Calculate 3 to the power of 2 and get 9.

$$16\left(9+9+3^{2}\right)$$

Add 9 and 9 to get 18.

$$16\left(18+3^{2}\right)$$

Calculate 3 to the power of 2 and get 9.

$$16\left(18+9\right)$$

Add 18 and 9 to get 27.

$$16\times 27$$

Multiply 16 and 27 to get 432.

$$432$$

Factor

$$2^{4}\times 3^{3}$$