Solve {l}{(2^{2}-1/2^1)^2}{2^4-1/2^2}

$$\left. \begin{array} { l } { ( 2 ^ { 2 } - \frac { 1 } { 2 ^ { 1 } } ) ^ { 2 } } \\ { 2 ^ { 4 } - \frac { 1 } { 2 ^ { 2 } } } \end{array} \right.$$

Sort

$$\frac{49}{4},\ \frac{63}{4}$$

Solution Steps

Calculate 2 to the power of 2 and get 4.

$$sort(\left(4-\frac{1}{2^{1}}\right)^{2},2^{4}-\frac{1}{2^{2}})$$

Calculate 2 to the power of 1 and get 2.

$$sort(\left(4-\frac{1}{2}\right)^{2},2^{4}-\frac{1}{2^{2}})$$

Subtract \frac{1}{2} from 4 to get \frac{7}{2}.

$$sort(\left(\frac{7}{2}\right)^{2},2^{4}-\frac{1}{2^{2}})$$

Calculate \frac{7}{2} to the power of 2 and get \frac{49}{4}.

$$sort(\frac{49}{4},2^{4}-\frac{1}{2^{2}})$$

Calculate 2 to the power of 4 and get 16.

$$sort(\frac{49}{4},16-\frac{1}{2^{2}})$$

Calculate 2 to the power of 2 and get 4.

$$sort(\frac{49}{4},16-\frac{1}{4})$$

Subtract \frac{1}{4} from 16 to get \frac{63}{4}.

$$sort(\frac{49}{4},\frac{63}{4})$$

The list values are already in order.

$$\frac{49}{4},\frac{63}{4}$$

Evaluate

$$\frac{49}{4},\ \frac{63}{4}$$