Solve {l}{{(2+x)}{(x+3)}=x^2}{text{Solvefor}ytext{where}}{y=-2}

$$\left. \begin{array} { l } { {(2 + x)} {(x + 3)} = x ^ {2} }\\ { \text{Solve for } y \text{ where} } \\ { y = -2 } \end{array} \right.$$

Solve for x, y

$$y=-2$$

Solution Steps

Consider the first equation. Use the distributive property to multiply 2+x by x+3 and combine like terms.

$$5x+6+x^{2}=x^{2}$$

Subtract x^{2} from both sides.

$$5x+6+x^{2}-x^{2}=0$$

Combine x^{2} and -x^{2} to get 0.

$$5x+6=0$$

Subtract 6 from both sides. Anything subtracted from zero gives its negation.

$$5x=-6$$

Divide both sides by 5.

$$x=-\frac{6}{5}$$

The system is now solved.

$$x=-\frac{6}{5} y=-2$$