Solve {l}{(18:3^{2})^{3}*0,5^2}{0,25*(3*2^3+4^2)-2,1^2}

$$\left. \begin{array} { l } { ( 18 : 3 ^ { 2 } ) ^ { 3 } \cdot 0,5 ^ { 2 } } \\ { 0,25 \cdot ( 3 \cdot 2 ^ { 3 } + 4 ^ { 2 } ) - 2,1 ^ { 2 } } \end{array} \right.$$

Sort

$$0,\ 8$$

Solution Steps

Calculate 3 to the power of 2 and get 9.

$$sort(\left(\frac{18}{9}\right)^{3}\times 0\times 5^{2};0,25\left(3\times 2^{3}+4^{2}\right)-2\times 1^{2})$$

Divide 18 by 9 to get 2.

$$sort(2^{3}\times 0\times 5^{2};0,25\left(3\times 2^{3}+4^{2}\right)-2\times 1^{2})$$

Calculate 2 to the power of 3 and get 8.

$$sort(8\times 0\times 5^{2};0,25\left(3\times 2^{3}+4^{2}\right)-2\times 1^{2})$$

Multiply 8 and 0 to get 0.

$$sort(0\times 5^{2};0,25\left(3\times 2^{3}+4^{2}\right)-2\times 1^{2})$$

Calculate 5 to the power of 2 and get 25.

$$sort(0\times 25;0,25\left(3\times 2^{3}+4^{2}\right)-2\times 1^{2})$$

Multiply 0 and 25 to get 0.

$$sort(0;0,25\left(3\times 2^{3}+4^{2}\right)-2\times 1^{2})$$

Calculate 2 to the power of 3 and get 8.

$$sort(0;0,25\left(3\times 8+4^{2}\right)-2\times 1^{2})$$

Multiply 3 and 8 to get 24.

$$sort(0;0,25\left(24+4^{2}\right)-2\times 1^{2})$$

Calculate 4 to the power of 2 and get 16.

$$sort(0;0,25\left(24+16\right)-2\times 1^{2})$$

Add 24 and 16 to get 40.

$$sort(0;0,25\times 40-2\times 1^{2})$$

Multiply 0,25 and 40 to get 10.

$$sort(0;10-2\times 1^{2})$$

Calculate 1 to the power of 2 and get 1.

$$sort(0;10-2\times 1)$$

Multiply 2 and 1 to get 2.

$$sort(0;10-2)$$

Subtract 2 from 10 to get 8.

$$sort(0;8)$$

The list values are already in order.

$$0;8$$

Evaluate

$$0,\ 8$$