Solve {l}{(-2+-1/2),(0-3/2)}{-2+-1/2}

$$\left. \begin{array} { l } { ( \frac { - 2 + - 1 } { 2 } ) , ( \frac { 0 - 3 } { 2 } ) } \\ { \frac { - 2 + - 1 } { 2 } } \end{array} \right.$$

Sort

$$-\frac{3}{2},\ -\frac{3}{2},\ -\frac{3}{2}$$

Solution Steps

Subtract 1 from -2 to get -3.

$$sort(\frac{-3}{2},\frac{0-3}{2},\frac{-2-1}{2})$$

Fraction \frac{-3}{2} can be rewritten as -\frac{3}{2} by extracting the negative sign.

$$sort(-\frac{3}{2},\frac{0-3}{2},\frac{-2-1}{2})$$

Subtract 3 from 0 to get -3.

$$sort(-\frac{3}{2},\frac{-3}{2},\frac{-2-1}{2})$$

Fraction \frac{-3}{2} can be rewritten as -\frac{3}{2} by extracting the negative sign.

$$sort(-\frac{3}{2},-\frac{3}{2},\frac{-2-1}{2})$$

Subtract 1 from -2 to get -3.

$$sort(-\frac{3}{2},-\frac{3}{2},\frac{-3}{2})$$

Fraction \frac{-3}{2} can be rewritten as -\frac{3}{2} by extracting the negative sign.

$$sort(-\frac{3}{2},-\frac{3}{2},-\frac{3}{2})$$

The list values are already in order.

$$-\frac{3}{2},-\frac{3}{2},-\frac{3}{2}$$

Evaluate

$$-\frac{3}{2},\ -\frac{3}{2},\ -\frac{3}{2}$$