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Solve for x, y, z
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x+3=y \frac{x+2}{y-2}=3 z=3+x
Reorder the equations.
y=x+3
Solve x+3=y for y.
\frac{x+2}{x+3-2}=3
Substitute x+3 for y in the equation \frac{x+2}{y-2}=3.
x=-\frac{1}{2}
Solve \frac{x+2}{x+3-2}=3 for x.
z=-\frac{1}{2}+3
Substitute -\frac{1}{2} for x in the equation z=x+3.
z=\frac{5}{2}
Calculate z from z=-\frac{1}{2}+3.
y=-\frac{1}{2}+3
Substitute -\frac{1}{2} for x in the equation y=x+3.
y=\frac{5}{2}
Calculate y from y=-\frac{1}{2}+3.
x=-\frac{1}{2} y=\frac{5}{2} z=\frac{5}{2}
The system is now solved.