Solve {l}{8/7*(-14/32)}{(-9/12)*(-60/3)}{45+(-9)}

$$\left. \begin{array} { l } { \frac { 8 } { 7 } \cdot ( - \frac { 14 } { 32 } ) } \\ { ( - \frac { 9 } { 12 } ) \cdot ( - \frac { 60 } { 3 } ) } \\ { 45 + ( - 9 ) } \end{array} \right.$$

Sort

$$-\frac{1}{2},\ 15,\ 36$$

Solution Steps

Reduce the fraction \frac{14}{32} to lowest terms by extracting and canceling out 2.

$$sort(\frac{8}{7}\left(-\frac{7}{16}\right),\left(-\frac{9}{12}\right)\left(-\frac{60}{3}\right),45-9)$$

Multiply \frac{8}{7} times -\frac{7}{16} by multiplying numerator times numerator and denominator times denominator.

$$sort(\frac{8\left(-7\right)}{7\times 16},\left(-\frac{9}{12}\right)\left(-\frac{60}{3}\right),45-9)$$

Do the multiplications in the fraction \frac{8\left(-7\right)}{7\times 16}.

$$sort(\frac{-56}{112},\left(-\frac{9}{12}\right)\left(-\frac{60}{3}\right),45-9)$$

Reduce the fraction \frac{-56}{112} to lowest terms by extracting and canceling out 56.

$$sort(-\frac{1}{2},\left(-\frac{9}{12}\right)\left(-\frac{60}{3}\right),45-9)$$

Reduce the fraction \frac{9}{12} to lowest terms by extracting and canceling out 3.

$$sort(-\frac{1}{2},-\frac{3}{4}\left(-\frac{60}{3}\right),45-9)$$

Divide 60 by 3 to get 20.

$$sort(-\frac{1}{2},-\frac{3}{4}\left(-20\right),45-9)$$

Express -\frac{3}{4}\left(-20\right) as a single fraction.

$$sort(-\frac{1}{2},\frac{-3\left(-20\right)}{4},45-9)$$

Multiply -3 and -20 to get 60.

$$sort(-\frac{1}{2},\frac{60}{4},45-9)$$

Divide 60 by 4 to get 15.

$$sort(-\frac{1}{2},15,45-9)$$

Subtract 9 from 45 to get 36.

$$sort(-\frac{1}{2},15,36)$$

Convert decimal numbers in the list -\frac{1}{2},15,36 to fractions.

$$-\frac{1}{2},15,36$$

Evaluate

$$-\frac{1}{2},\ 15,\ 36$$