Solve {l}{7/3+(45/42)}{-77/42}

$$\left. \begin{array} { l } { \frac { 7 } { 3 } + ( \frac { 45 } { 42 } ) } \\ { - \frac { 77 } { 42 } } \end{array} \right.$$

Evaluate

$$\frac{11}{7}\approx 1.571428571$$

Solution Steps

Reduce the fraction \frac{45}{42} to lowest terms by extracting and canceling out 3.

$$\frac{7}{3}+\frac{15}{14}-\frac{77}{42}$$

Least common multiple of 3 and 14 is 42. Convert \frac{7}{3} and \frac{15}{14} to fractions with denominator 42.

$$\frac{98}{42}+\frac{45}{42}-\frac{77}{42}$$

Since \frac{98}{42} and \frac{45}{42} have the same denominator, add them by adding their numerators.

$$\frac{98+45}{42}-\frac{77}{42}$$

Add 98 and 45 to get 143.

$$\frac{143}{42}-\frac{77}{42}$$

Since \frac{143}{42} and \frac{77}{42} have the same denominator, subtract them by subtracting their numerators.

$$\frac{143-77}{42}$$

Subtract 77 from 143 to get 66.

$$\frac{66}{42}$$

Reduce the fraction \frac{66}{42} to lowest terms by extracting and canceling out 6.

$$\frac{11}{7}$$

Factor

$$\frac{11}{7} = 1\frac{4}{7} = 1.5714285714285714$$