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\frac{3}{7}A+\frac{1}{2}=15
Consider the first equation. Reduce the fraction \frac{3}{6} to lowest terms by extracting and canceling out 3.
\frac{3}{7}A=15-\frac{1}{2}
Subtract \frac{1}{2} from both sides.
\frac{3}{7}A=\frac{29}{2}
Subtract \frac{1}{2} from 15 to get \frac{29}{2}.
A=\frac{29}{2}\times \frac{7}{3}
Multiply both sides by \frac{7}{3}, the reciprocal of \frac{3}{7}.
A=\frac{203}{6}
Multiply \frac{29}{2} and \frac{7}{3} to get \frac{203}{6}.
\frac{3}{4}\times \frac{203}{6}-B=2
Consider the second equation. Insert the known values of variables into the equation.
\frac{203}{8}-B=2
Multiply \frac{3}{4} and \frac{203}{6} to get \frac{203}{8}.
-B=2-\frac{203}{8}
Subtract \frac{203}{8} from both sides.
-B=-\frac{187}{8}
Subtract \frac{203}{8} from 2 to get -\frac{187}{8}.
B=\frac{-\frac{187}{8}}{-1}
Divide both sides by -1.
B=\frac{-187}{8\left(-1\right)}
Express \frac{-\frac{187}{8}}{-1} as a single fraction.
B=\frac{-187}{-8}
Multiply 8 and -1 to get -8.
B=\frac{187}{8}
Fraction \frac{-187}{-8} can be simplified to \frac{187}{8} by removing the negative sign from both the numerator and the denominator.
A=\frac{203}{6} B=\frac{187}{8}
The system is now solved.