Solve {l}{+4*7}{128/29}{+4(9-8)}{6-5}

$$\left. \begin{array} { l } { + 4 \times 7 } \\ { \frac { 128 } { 29 } } \\ { + 4 ( 9 - 8 ) } \\ { 6 - 5 } \end{array} \right.$$

Sort

$$1,4,\frac{128}{29},28$$

Solution Steps

Multiply 4 and 7 to get 28.

$$sort(28,\frac{128}{29},4\left(9-8\right),6-5)$$

Subtract 8 from 9 to get 1.

$$sort(28,\frac{128}{29},4\times 1,6-5)$$

Multiply 4 and 1 to get 4.

$$sort(28,\frac{128}{29},4,6-5)$$

Subtract 5 from 6 to get 1.

$$sort(28,\frac{128}{29},4,1)$$

Convert decimal numbers in the list 28,\frac{128}{29},4,1 to fractions.

$$28,\frac{128}{29},4,1$$

To sort the list, start from a single element 28.

$$28$$

Insert \frac{128}{29} to the appropriate location in the new list.

$$\frac{128}{29},28$$

Insert 4 to the appropriate location in the new list.

$$4,\frac{128}{29},28$$

Insert 1 to the appropriate location in the new list.

$$1,4,\frac{128}{29},28$$

Evaluate

$$28,\ \frac{128}{29},\ 4,\ 1$$