Solve {l}{y=frac{x^frac{3{4}}sqrt{x^2+1}}{(3x+2)^5}}{z=f{(x)}}{text{Solvefor}atext{where}}{a=z}

$$\left. \begin{array} { l } { y = \frac{x ^ {\frac{3}{4}} \sqrt{x ^ {2} + 1}}{{(3 x + 2)} ^ {5}} }\\ { z = f {(x)} }\\ { \text{Solve for } a \text{ where} } \\ { a = z } \end{array} \right.$$

Solve for x, y, z

$$\left\{\begin{matrix}x=\frac{a}{f}\text{, }y=\left(\frac{f}{3a+2f}\right)^{5}\times \left(\frac{a}{f^{\frac{7}{3}}}\right)^{\frac{3}{4}}\sqrt{a^{2}+f^{2}}\text{, }z=a\text{, }&\left(a\leq 0\text{ and }f<0\right)\text{ or }\left(a\geq 0\text{ and }f>0\right)\\x\geq 0\text{, }y=\frac{x^{\frac{3}{4}}\sqrt{x^{2}+1}}{\left(3x+2\right)^{5}}\text{, }z=0\text{, }&a=0\text{ and }f=0\end{matrix}\right.$$