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Solve for y, z, a
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\frac{y}{\frac{2}{3}}=6\times \frac{25}{24}
Consider the first equation. Divide 6 by \frac{24}{25} by multiplying 6 by the reciprocal of \frac{24}{25}.
\frac{y}{\frac{2}{3}}=\frac{25}{4}
Multiply 6 and \frac{25}{24} to get \frac{25}{4}.
y=\frac{25}{4}\times \frac{2}{3}
Multiply both sides by \frac{2}{3}.
y=\frac{25}{6}
Multiply \frac{25}{4} and \frac{2}{3} to get \frac{25}{6}.
z=\frac{25}{6}
Consider the second equation. Insert the known values of variables into the equation.
a=\frac{25}{6}
Consider the third equation. Insert the known values of variables into the equation.
y=\frac{25}{6} z=\frac{25}{6} a=\frac{25}{6}
The system is now solved.