Solve for x, y, z
z=608
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y=8+6\left(13-3\right)^{2}
Consider the second equation. Insert the known values of variables into the equation.
y=8+6\times 10^{2}
Subtract 3 from 13 to get 10.
y=8+6\times 100
Calculate 10 to the power of 2 and get 100.
y=8+600
Multiply 6 and 100 to get 600.
y=608
Add 8 and 600 to get 608.
z=608
Consider the third equation. Insert the known values of variables into the equation.
x=13 y=608 z=608
The system is now solved.
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