Solve {l}{x=-4}{y=2}{z=4+y-23+6x-12}{text{Solvefor}atext{where}}{a=z}

$$\left. \begin{array} { l } { x = -4 }\\ { y = 2 }\\ { z = 4 + y - 23 + 6 x - 12 }\\ { \text{Solve for } a \text{ where} } \\ { a = z } \end{array} \right.$$

Solve for x, y, z, a

$$a=-53$$

Solution Steps

Consider the third equation. Insert the known values of variables into the equation.

$$z=4+2-23+6\left(-4\right)-12$$

Add 4 and 2 to get 6.

$$z=6-23+6\left(-4\right)-12$$

Subtract 23 from 6 to get -17.

$$z=-17+6\left(-4\right)-12$$

Multiply 6 and -4 to get -24.

$$z=-17-24-12$$

Subtract 24 from -17 to get -41.

$$z=-41-12$$

Subtract 12 from -41 to get -53.

$$z=-53$$

Consider the fourth equation. Insert the known values of variables into the equation.

$$a=-53$$

The system is now solved.

$$x=-4 y=2 z=-53 a=-53$$