Solve {l}{x=-4}{y={(2.53*10^-5)}{(4*10^0)}}{text{Solvefor}ztext{where}}{z=y}

$$\left. \begin{array} { l } { x = -4 }\\ { y = {(2.53 \cdot 10 ^ {-5})} {(4 \cdot 10 ^ {0})} }\\ { \text{Solve for } z \text{ where} } \\ { z = y } \end{array} \right.$$

Solve for x, y, z

$$z=0.0001012$$

Solution Steps

Consider the second equation. To multiply powers of the same base, add their exponents. Add -5 and 0 to get -5.

$$y=2.53\times 10^{-5}\times 4$$

Calculate 10 to the power of -5 and get \frac{1}{100000}.

$$y=2.53\times \frac{1}{100000}\times 4$$

Multiply 2.53 and \frac{1}{100000} to get \frac{253}{10000000}.

$$y=\frac{253}{10000000}\times 4$$

Multiply \frac{253}{10000000} and 4 to get \frac{253}{2500000}.

$$y=\frac{253}{2500000}$$

Consider the third equation. Insert the known values of variables into the equation.

$$z=\frac{253}{2500000}$$

The system is now solved.

$$x=-4 y=\frac{253}{2500000} z=\frac{253}{2500000}$$