Solve {l}{x=-3}{y=18x^-3}{text{Solvefor}ztext{where}}{z=y}

$$\left. \begin{array} { l } { x = -3 }\\ { y = 18 x ^ {-3} }\\ { \text{Solve for } z \text{ where} } \\ { z = y } \end{array} \right.$$

Solve for x, y, z

$$z=-\frac{2}{3}\approx -0.666666667$$

Solution Steps

Consider the second equation. Insert the known values of variables into the equation.

$$y=18\left(-3\right)^{-3}$$

Calculate -3 to the power of -3 and get -\frac{1}{27}.

$$y=18\left(-\frac{1}{27}\right)$$

Multiply 18 and -\frac{1}{27} to get -\frac{2}{3}.

$$y=-\frac{2}{3}$$

Consider the third equation. Insert the known values of variables into the equation.

$$z=-\frac{2}{3}$$

The system is now solved.

$$x=-3 y=-\frac{2}{3} z=-\frac{2}{3}$$