Solve {l}{x+6y=19}{-y=3}{z=3+y}{text{Solvefor}atext{where}}{a=z}

$$\left. \begin{array} { l } { x + 6 y = 19 }\\ { -y = 3 }\\ { z = 3 + y }\\ { \text{Solve for } a \text{ where} } \\ { a = z } \end{array} \right.$$

Solve for x, y, z, a

$$a=0$$

Solution Steps

Consider the second equation. Divide both sides by -1.

$$y=-3$$

Consider the third equation. Insert the known values of variables into the equation.

$$z=3-3$$

Subtract 3 from 3 to get 0.

$$z=0$$

Consider the fourth equation. Insert the known values of variables into the equation.

$$a=0$$

Consider the first equation. Insert the known values of variables into the equation.

$$x+6\left(-3\right)=19$$

Multiply 6 and -3 to get -18.

$$x-18=19$$

Add 18 to both sides.

$$x=19+18$$

Add 19 and 18 to get 37.

$$x=37$$

The system is now solved.

$$x=37 y=-3 z=0 a=0$$