Solve {l}{x+5=0}{y=x}{z=y}{a=z}{b=a}{c=b}{text{Solvefor}dtext{where}}{d=c}

$$\left. \begin{array} { l } { x + 5 = 0 }\\ { y = x }\\ { z = y }\\ { a = z }\\ { b = a }\\ { c = b }\\ { \text{Solve for } d \text{ where} } \\ { d = c } \end{array} \right.$$

Solve for x, y, z, a, b, c, d

$$d=-5$$

Solution Steps

Consider the first equation. Subtract 5 from both sides. Anything subtracted from zero gives its negation.

$$x=-5$$

Consider the second equation. Insert the known values of variables into the equation.

$$y=-5$$

Consider the third equation. Insert the known values of variables into the equation.

$$z=-5$$

Consider the fourth equation. Insert the known values of variables into the equation.

$$a=-5$$

Consider the fifth equation. Insert the known values of variables into the equation.

$$b=-5$$

Consider the equation (6). Insert the known values of variables into the equation.

$$c=-5$$

Consider the equation (7). Insert the known values of variables into the equation.

$$d=-5$$

The system is now solved.

$$x=-5 y=-5 z=-5 a=-5 b=-5 c=-5 d=-5$$