Solve {l}{u=-3}{a=-4}{t=6}{v={(2)}at^2}{text{Solvefor}wtext{where}}{w=v}

$$\left. \begin{array} { l } { u = -3 }\\ { a = -4 }\\ { t = 6 }\\ { v = {(2)} a t ^ {2} }\\ { \text{Solve for } w \text{ where} } \\ { w = v } \end{array} \right.$$

Solve for u, a, t, v, w

$$w=-288$$

Solution Steps

Consider the fourth equation. Insert the known values of variables into the equation.

$$v=2\left(-4\right)\times 6^{2}$$

Multiply 2 and -4 to get -8.

$$v=-8\times 6^{2}$$

Calculate 6 to the power of 2 and get 36.

$$v=-8\times 36$$

Multiply -8 and 36 to get -288.

$$v=-288$$

Consider the fifth equation. Insert the known values of variables into the equation.

$$w=-288$$

The system is now solved.

$$u=-3 a=-4 t=6 v=-288 w=-288$$