Solve {l}{p=5/6}{q={(frac{7*{(2)}+1}{2})}-p}{r=q}{text{Solvefor}stext{where}}{s=r}

$$\left. \begin{array} { l } { p = \frac{5}{6} }\\ { q = {(\frac{7 \cdot {(2)} + 1}{2})} - p }\\ { r = q }\\ { \text{Solve for } s \text{ where} } \\ { s = r } \end{array} \right.$$

Solve for p, q, r, s

$$s = \frac{20}{3} = 6\frac{2}{3} \approx 6.666666667$$

Solution Steps

Consider the second equation. Insert the known values of variables into the equation.

$$q=\frac{7\times 2+1}{2}-\frac{5}{6}$$

Multiply 7 and 2 to get 14.

$$q=\frac{14+1}{2}-\frac{5}{6}$$

Add 14 and 1 to get 15.

$$q=\frac{15}{2}-\frac{5}{6}$$

Subtract \frac{5}{6} from \frac{15}{2} to get \frac{20}{3}.

$$q=\frac{20}{3}$$

Consider the third equation. Insert the known values of variables into the equation.

$$r=\frac{20}{3}$$

Consider the fourth equation. Insert the known values of variables into the equation.

$$s=\frac{20}{3}$$

The system is now solved.

$$p=\frac{5}{6} q=\frac{20}{3} r=\frac{20}{3} s=\frac{20}{3}$$