Solve {l}{n=3^-2*9^(frac{3{2)}}+2^3}{o=35}{p=o}{q=p}{text{Solvefor}rtext{where}}{r=q}

$$\left. \begin{array} { l } { n = 3 ^ {-2} \cdot 9 ^ {{(\frac{3}{2})}} + 2 ^ {3} }\\ { o = 35 }\\ { p = o }\\ { q = p }\\ { \text{Solve for } r \text{ where} } \\ { r = q } \end{array} \right.$$

Solve for n, o, p, q, r

$$r=35$$

Solution Steps

Consider the first equation. Calculate 3 to the power of -2 and get \frac{1}{9}.

$$n=\frac{1}{9}\times 9^{\frac{3}{2}}+2^{3}$$

Calculate 9 to the power of \frac{3}{2} and get 27.

$$n=\frac{1}{9}\times 27+2^{3}$$

Multiply \frac{1}{9} and 27 to get 3.

$$n=3+2^{3}$$

Calculate 2 to the power of 3 and get 8.

$$n=3+8$$

Add 3 and 8 to get 11.

$$n=11$$

The system is now solved.

$$n=11 o=35 p=35 q=35 r=35$$