Solve {l}{g{(x)}=0*0*0*7x^2+0}{h=9x}{text{Solvefor}itext{where}}{i=h}

$$\left. \begin{array} { l } { g {(x)} = 0 \cdot 0 \cdot 0 \cdot 7 x ^ {2} + 0 }\\ { h = 9 x }\\ { \text{Solve for } i \text{ where} } \\ { i = h } \end{array} \right.$$

Solve for g, x, h

$$x=\frac{1}{9}i\approx 0.111111111i$$

$$g=0$$

$$h=i$$

Solution Steps

Consider the third equation. Swap sides so that all variable terms are on the left hand side.

$$h=i$$

Consider the second equation. Insert the known values of variables into the equation.

$$i=9x$$

Divide both sides by 9.

$$\frac{i}{9}=x$$

Divide i by 9 to get \frac{1}{9}i.

$$\frac{1}{9}i=x$$

Swap sides so that all variable terms are on the left hand side.

$$x=\frac{1}{9}i$$

Consider the first equation. Insert the known values of variables into the equation.

$$g\times \left(\frac{1}{9}i\right)=0\times 0\times 0\times 7\times \left(\frac{1}{9}i\right)^{2}+0$$

Multiply 0 and 0 to get 0.

$$g\times \left(\frac{1}{9}i\right)=0\times 0\times 7\times \left(\frac{1}{9}i\right)^{2}+0$$

Multiply 0 and 0 to get 0.

$$g\times \left(\frac{1}{9}i\right)=0\times 7\times \left(\frac{1}{9}i\right)^{2}+0$$

Multiply 0 and 7 to get 0.

$$g\times \left(\frac{1}{9}i\right)=0\times \left(\frac{1}{9}i\right)^{2}+0$$

Calculate \frac{1}{9}i to the power of 2 and get -\frac{1}{81}.

$$g\times \left(\frac{1}{9}i\right)=0\left(-\frac{1}{81}\right)+0$$

Multiply 0 and -\frac{1}{81} to get 0.

$$g\times \left(\frac{1}{9}i\right)=0+0$$

Add 0 and 0 to get 0.

$$g\times \left(\frac{1}{9}i\right)=0$$

Divide both sides by \frac{1}{9}i. Zero divided by any non-zero number gives zero.

$$g=0$$

The system is now solved.

$$g=0 x=\frac{1}{9}i h=i$$