Solve {l}{a=3}{b=4}{x=5}{y={(x+a)}{(x+b)}}{text{Solvefor}ztext{where}}{z=y}

$$\left. \begin{array} { l } { a = 3 }\\ { b = 4 }\\ { x = 5 }\\ { y = {(x + a)} {(x + b)} }\\ { \text{Solve for } z \text{ where} } \\ { z = y } \end{array} \right.$$

Solve for a, b, x, y, z

$$z=72$$

Solution Steps

Consider the fourth equation. Insert the known values of variables into the equation.

$$y=\left(5+3\right)\left(5+4\right)$$

Add 5 and 3 to get 8.

$$y=8\left(5+4\right)$$

Add 5 and 4 to get 9.

$$y=8\times 9$$

Multiply 8 and 9 to get 72.

$$y=72$$

Consider the fifth equation. Insert the known values of variables into the equation.

$$z=72$$

The system is now solved.

$$a=3 b=4 x=5 y=72 z=72$$