Solve {l}{7x-3=53}{y=7x-53+3}{text{Solvefor}ztext{where}}{z=y}

$$\left. \begin{array} { l } { 7 x - 3 = 53 }\\ { y = 7 x - 53 + 3 }\\ { \text{Solve for } z \text{ where} } \\ { z = y } \end{array} \right.$$

Solve for x, y, z

$$z=6$$

Solution Steps

Consider the first equation. Add 3 to both sides.

$$7x=53+3$$

Add 53 and 3 to get 56.

$$7x=56$$

Divide both sides by 7.

$$x=\frac{56}{7}$$

Divide 56 by 7 to get 8.

$$x=8$$

Consider the second equation. Insert the known values of variables into the equation.

$$y=7\times 8-53+3$$

Multiply 7 and 8 to get 56.

$$y=56-53+3$$

Subtract 53 from 56 to get 3.

$$y=3+3$$

Add 3 and 3 to get 6.

$$y=6$$

Consider the third equation. Insert the known values of variables into the equation.

$$z=6$$

The system is now solved.

$$x=8 y=6 z=6$$