Solve for x, y, z
z=1
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5x-32=0\times 3x
Consider the first equation. Multiply 4 and 8 to get 32.
5x-32=0x
Multiply 0 and 3 to get 0.
5x-32=0
Anything times zero gives zero.
5x=32
Add 32 to both sides. Anything plus zero gives itself.
x=\frac{32}{5}
Divide both sides by 5.
x=\frac{32}{5} y=1 z=1
The system is now solved.
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