Solve {l}{5-7/8b={(frac{11*{(2)}+1}{2})}}{c=12}{text{Solvefor}dtext{where}}{d=c}

$$\left. \begin{array} { l } { 5 - \frac{7}{8} b = {(\frac{11 \cdot {(2)} + 1}{2})} }\\ { c = 12 }\\ { \text{Solve for } d \text{ where} } \\ { d = c } \end{array} \right.$$

Solve for b, c, d

$$d=12$$

Solution Steps

Consider the first equation. Multiply both sides of the equation by 8, the least common multiple of 8,2.

$$40-7b=4\left(11\times 2+1\right)$$

Multiply 11 and 2 to get 22.

$$40-7b=4\left(22+1\right)$$

Add 22 and 1 to get 23.

$$40-7b=4\times 23$$

Multiply 4 and 23 to get 92.

$$40-7b=92$$

Subtract 40 from both sides.

$$-7b=92-40$$

Subtract 40 from 92 to get 52.

$$-7b=52$$

Divide both sides by -7.

$$b=-\frac{52}{7}$$

The system is now solved.

$$b=-\frac{52}{7} c=12 d=12$$