Solve {l}{5{(w+2)}=2}{x={(2w+2)}}{text{Solvefor}ytext{where}}{y=x}

$$\left. \begin{array} { l } { 5 {(w + 2)} = 2 }\\ { x = {(2 w + 2)} }\\ { \text{Solve for } y \text{ where} } \\ { y = x } \end{array} \right.$$

Solve for w, x, y

$$y = -\frac{6}{5} = -1\frac{1}{5} = -1.2$$

Solution Steps

Consider the first equation. Divide both sides by 5.

$$w+2=\frac{2}{5}$$

Subtract 2 from both sides.

$$w=\frac{2}{5}-2$$

Subtract 2 from \frac{2}{5} to get -\frac{8}{5}.

$$w=-\frac{8}{5}$$

Consider the second equation. Insert the known values of variables into the equation.

$$x=2\left(-\frac{8}{5}\right)+2$$

Multiply 2 and -\frac{8}{5} to get -\frac{16}{5}.

$$x=-\frac{16}{5}+2$$

Add -\frac{16}{5} and 2 to get -\frac{6}{5}.

$$x=-\frac{6}{5}$$

Consider the third equation. Insert the known values of variables into the equation.

$$y=-\frac{6}{5}$$

The system is now solved.

$$w=-\frac{8}{5} x=-\frac{6}{5} y=-\frac{6}{5}$$