Solve {l}{5{(5-7x)}=8}{y=0}{text{Solvefor}ztext{where}}{z=y}

$$\left. \begin{array} { l } { 5 {(5 - 7 x)} = 8 }\\ { y = 0 }\\ { \text{Solve for } z \text{ where} } \\ { z = y } \end{array} \right.$$

Solve for x, y, z

$$z=0$$

Solution Steps

Consider the first equation. Divide both sides by 5.

$$5-7x=\frac{8}{5}$$

Subtract 5 from both sides.

$$-7x=\frac{8}{5}-5$$

Subtract 5 from \frac{8}{5} to get -\frac{17}{5}.

$$-7x=-\frac{17}{5}$$

Divide both sides by -7.

$$x=\frac{-\frac{17}{5}}{-7}$$

Express \frac{-\frac{17}{5}}{-7} as a single fraction.

$$x=\frac{-17}{5\left(-7\right)}$$

Multiply 5 and -7 to get -35.

$$x=\frac{-17}{-35}$$

Fraction \frac{-17}{-35} can be simplified to \frac{17}{35} by removing the negative sign from both the numerator and the denominator.

$$x=\frac{17}{35}$$

The system is now solved.

$$x=\frac{17}{35} y=0 z=0$$