Solve {l}{4y-3=5}{z=y+2}{text{Solvefor}atext{where}}{a=z}

$$\left. \begin{array} { l } { 4 y - 3 = 5 }\\ { z = y + 2 }\\ { \text{Solve for } a \text{ where} } \\ { a = z } \end{array} \right.$$

Solve for y, z, a

$$a=4$$

Solution Steps

Consider the first equation. Add 3 to both sides.

$$4y=5+3$$

Add 5 and 3 to get 8.

$$4y=8$$

Divide both sides by 4.

$$y=\frac{8}{4}$$

Divide 8 by 4 to get 2.

$$y=2$$

Consider the second equation. Insert the known values of variables into the equation.

$$z=2+2$$

Add 2 and 2 to get 4.

$$z=4$$

Consider the third equation. Insert the known values of variables into the equation.

$$a=4$$

The system is now solved.

$$y=2 z=4 a=4$$