Solve {l}{4{(x+2)}=3{(x-5)}}{y=x}{text{Solvefor}ztext{where}}{z=y}

$$\left. \begin{array} { l } { 4 {(x + 2)} = 3 {(x - 5)} }\\ { y = x }\\ { \text{Solve for } z \text{ where} } \\ { z = y } \end{array} \right.$$

Solve for x, y, z

$$z=-23$$

Solution Steps

Consider the first equation. Use the distributive property to multiply 4 by x+2.

$$4x+8=3\left(x-5\right)$$

Use the distributive property to multiply 3 by x-5.

$$4x+8=3x-15$$

Subtract 3x from both sides.

$$4x+8-3x=-15$$

Combine 4x and -3x to get x.

$$x+8=-15$$

Subtract 8 from both sides.

$$x=-15-8$$

Subtract 8 from -15 to get -23.

$$x=-23$$

Consider the second equation. Insert the known values of variables into the equation.

$$y=-23$$

Consider the third equation. Insert the known values of variables into the equation.

$$z=-23$$

The system is now solved.

$$x=-23 y=-23 z=-23$$