Solve {l}{4{(9-x)}=52}{y=x}{z=y}{text{Solvefor}atext{where}}{a=z}

$$\left. \begin{array} { l } { 4 {(9 - x)} = 52 }\\ { y = x }\\ { z = y }\\ { \text{Solve for } a \text{ where} } \\ { a = z } \end{array} \right.$$

Solve for x, y, z, a

$$a=-4$$

Solution Steps

Consider the first equation. Divide both sides by 4.

$$9-x=\frac{52}{4}$$

Divide 52 by 4 to get 13.

$$9-x=13$$

Subtract 9 from both sides.

$$-x=13-9$$

Subtract 9 from 13 to get 4.

$$-x=4$$

Divide both sides by -1.

$$x=-4$$

Consider the second equation. Insert the known values of variables into the equation.

$$y=-4$$

Consider the third equation. Insert the known values of variables into the equation.

$$z=-4$$

Consider the fourth equation. Insert the known values of variables into the equation.

$$a=-4$$

The system is now solved.

$$x=-4 y=-4 z=-4 a=-4$$