Solve for x, y, z
z=10
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\frac{4\times 7}{3\times 7+5}=x
Consider the first equation. Divide 4 by \frac{3\times 7+5}{7} by multiplying 4 by the reciprocal of \frac{3\times 7+5}{7}.
\frac{28}{3\times 7+5}=x
Multiply 4 and 7 to get 28.
\frac{28}{21+5}=x
Multiply 3 and 7 to get 21.
\frac{28}{26}=x
Add 21 and 5 to get 26.
\frac{14}{13}=x
Reduce the fraction \frac{28}{26} to lowest terms by extracting and canceling out 2.
x=\frac{14}{13}
Swap sides so that all variable terms are on the left hand side.
x=\frac{14}{13} y=10 z=10
The system is now solved.
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