Solve {l}{4/{(frac{3*{(7)}+5}{7})}=x}{y=10}{z=y}{a=z}{text{Solvefor}btext{where}}{b=a}

$$\left. \begin{array} { l } { 4 / {(\frac{3 \cdot {(7)} + 5}{7})} = x }\\ { y = 10 }\\ { z = y }\\ { a = z }\\ { \text{Solve for } b \text{ where} } \\ { b = a } \end{array} \right.$$

Solve for x, y, z, a, b

$$b=10$$

Solution Steps

Consider the first equation. Divide 4 by \frac{3\times 7+5}{7} by multiplying 4 by the reciprocal of \frac{3\times 7+5}{7}.

$$\frac{4\times 7}{3\times 7+5}=x$$

Multiply 4 and 7 to get 28.

$$\frac{28}{3\times 7+5}=x$$

Multiply 3 and 7 to get 21.

$$\frac{28}{21+5}=x$$

Add 21 and 5 to get 26.

$$\frac{28}{26}=x$$

Reduce the fraction \frac{28}{26} to lowest terms by extracting and canceling out 2.

$$\frac{14}{13}=x$$

Swap sides so that all variable terms are on the left hand side.

$$x=\frac{14}{13}$$

The system is now solved.

$$x=\frac{14}{13} y=10 z=10 a=10 b=10$$