Solve {l}{4+4x/5-1=0*2x-3/2}{y=0}{text{Solvefor}ztext{where}}{z=y}

$$\left. \begin{array} { l } { 4 + \frac{4 x}{5} - 1 = 0 \cdot 2 x - \frac{3}{2} }\\ { y = 0 }\\ { \text{Solve for } z \text{ where} } \\ { z = y } \end{array} \right.$$

Solve for x, y, z

$$z=0$$

Solution Steps

Consider the first equation. Multiply both sides of the equation by 10, the least common multiple of 5,2.

$$40+2\times 4x-10=0\times 2x-15$$

Multiply 2 and 4 to get 8.

$$40+8x-10=0\times 2x-15$$

Subtract 10 from 40 to get 30.

$$30+8x=0\times 2x-15$$

Multiply 0 and 2 to get 0.

$$30+8x=0x-15$$

Anything times zero gives zero.

$$30+8x=0-15$$

Subtract 15 from 0 to get -15.

$$30+8x=-15$$

Subtract 30 from both sides.

$$8x=-15-30$$

Subtract 30 from -15 to get -45.

$$8x=-45$$

Divide both sides by 8.

$$x=-\frac{45}{8}$$

The system is now solved.

$$x=-\frac{45}{8} y=0 z=0$$