Solve {l}{3y+2x=17}{7y=21}{z=-1}{text{Solvefor}atext{where}}{a=z}

$$\left. \begin{array} { l } { 3 y + 2 x = 17 }\\ { 7 y = 21 }\\ { z = -1 }\\ { \text{Solve for } a \text{ where} } \\ { a = z } \end{array} \right.$$

Solve for y, x, z, a

$$a=-1$$

Solution Steps

Consider the second equation. Divide both sides by 7.

$$y=\frac{21}{7}$$

Divide 21 by 7 to get 3.

$$y=3$$

Consider the first equation. Insert the known values of variables into the equation.

$$3\times 3+2x=17$$

Multiply 3 and 3 to get 9.

$$9+2x=17$$

Subtract 9 from both sides.

$$2x=17-9$$

Subtract 9 from 17 to get 8.

$$2x=8$$

Divide both sides by 2.

$$x=\frac{8}{2}$$

Divide 8 by 2 to get 4.

$$x=4$$

The system is now solved.

$$y=3 x=4 z=-1 a=-1$$