Solve {l}{3x/9=2}{y={(x^2-x)}/2x}{text{Solvefor}ztext{where}}{z=y}

$$\left. \begin{array} { l } { 3 x / 9 = 2 }\\ { y = {(x ^ {2} - x)} / 2 x }\\ { \text{Solve for } z \text{ where} } \\ { z = y } \end{array} \right.$$

Solve for x, y, z

$$z=90$$

Solution Steps

Consider the first equation. Multiply both sides by 9.

$$3x=2\times 9$$

Multiply 2 and 9 to get 18.

$$3x=18$$

Divide both sides by 3.

$$x=\frac{18}{3}$$

Divide 18 by 3 to get 6.

$$x=6$$

Consider the second equation. Insert the known values of variables into the equation.

$$y=\frac{6^{2}-6}{2}\times 6$$

Calculate 6 to the power of 2 and get 36.

$$y=\frac{36-6}{2}\times 6$$

Subtract 6 from 36 to get 30.

$$y=\frac{30}{2}\times 6$$

Divide 30 by 2 to get 15.

$$y=15\times 6$$

Multiply 15 and 6 to get 90.

$$y=90$$

Consider the third equation. Insert the known values of variables into the equation.

$$z=90$$

The system is now solved.

$$x=6 y=90 z=90$$