Solve for x, y, z, a
a=4
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3x+12-2x=0
Consider the first equation. Subtract 2x from both sides.
x+12=0
Combine 3x and -2x to get x.
x=-12
Subtract 12 from both sides. Anything subtracted from zero gives its negation.
x=-12 y=4 z=4 a=4
The system is now solved.
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